Let $A$ and $B$ be two matrices of order $m\times n$.Then:
<aside> 💡 $A$ is equivalent to $B$ if $B=QAP$ for some invertible $n\times n$ matrix$~P$ and for some invertible $m\times m$ matrix $Q$.
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Other Characteristics:
Consider a linear transformation $T:V\rightarrow W$, two ordered bases $\beta_{1}$ and $\beta_2$ for $V$, and two ordered bases $\gamma_1$ and $\gamma_2$ for $W$.
Let $A$ be the matrix corresponding to $T$ with respect to the bases $\beta_1$ and $\gamma_1$ and $B$ be the matrix corresponding to $T$ with respect to the bases $\beta_2$ and $\gamma_2$.
<aside> 💡 Then $A$ is equivalent to B.
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For $P$ → express the ordered basis $\beta_2$ in terms of ordered basis $\beta_1$. For $Q$ → express the ordered basis $\gamma_1$ in terms of ordered basis $\gamma_2$.
<aside> 💡 An $n\times n$ matrix $A$ is similar to an $n\times n$ matrix $B$ if there exists an $n\times n$ invertible matrix $P$ such that $B=P^{-1}AP$.
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Similarity is an equivalence relation:
Suppose $A$ and $B$ are similar matrices. Then the following properties hold:
<aside> 💡 1. $A$ and $B$ are equivalent. 2. $A$ and $B$ have the same rank. 3. $det(B)=det(P^{-1}AP)=det(P^{-1})det(A)det(P)=det(A)$
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